1/2*(x+2)+1/3 (x+3)+1/5*(x-5)=2 (x^2-y^2) ^2/x^2+2xy+y^2) /

Question

1/2*(x+2)+1/3 (x+3)+1/5*(x-5)=2 (x^2-y^2) ^2/x^2+2xy+y^2) / (1/x^2-1/y^2)

ppsm89 · Accepted Answer

0,5 х +1+1/3 х +1+0,2 х-1=2 15/30 х +10/30 х +6/30 х=2-1 1 1/30=1 Ответ: 31/30

1/2(x+2)+1/3 (x+3)+1/5(x-5)=2 (x^2-y^2) ^2/x^2+2xy+y^2) /