Задание:
m^2+4m-5 m^2+7m+10 (7 (m-2) _ m+2). 2m^2+4m+8 (m^3-8 m^2+2m=4) m-32a+3 . (2a^2+3a _ 3a+2)+4a-1 _ a-12a-3 (4a^2+12a+9 2a+3) 2a-3 a (9x^2+8 _ 1+4). 3x-1 (27x^3-1 3x-1 9x^2+3x+1) 3x+1
Решение:
1. m^2+4m-5D=4^2+4*5=36m1=(-4+6) /2=1 m2=-5 (x-1) (x+5) m^2+7m+10D=7^2-4*10=9m1=(-7-3) /2=-5m2=-4/2=-2 (x+2) (x+5) (x+5) (x-1) / (x+2) (x+5)=(x-1) / (x+2) 2. 1) (7 (m-2) / (m-2) (m^2+2m+4) — (m+2) / (m+2) ^ 2)=(7/ (m+2) ^2) — (m+2) / (m+2) ^2)=(7-m+2) / (m+2) ^2=(9-m) / (m+2) ^2) 2) (9+m) / (m+2) ^2*(2 (m^2+2m+4) / (m-3)=(9-m)*2/ (m-3)=(18-2m) / (m-3) http: //cs316727.vk.me/v316727766/d6a2/W8PhtQmEBQo.jpghttp: //cs316727.vk.me/v316727766/d698/UwKK0-BP820.jpg
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