Решите уравнения: а) sint (2cost+1)=0 б) (sint -1)

a) sin (t)*2cos (t)+1)=0 1) sin (t)=0 t=pi*n 2) 2*cos (t)+1=0 2*cos (t)=-1 cos (t)=-1/2 t=±arccos (-1/2)+2*pi/n t=± (4*pi/3)+2*pi*n б) (sin (t) -1)*(cos (t)+1)=0 1) sin (t) -1=0 sin (t)=1 t=(pi/2)+2*pi*n 2) cos (t)+1=0 cos (t)=-1 t=pi+2*pi*nв) cos (t)*(2sin (t)+1)=0 1) cos (t)=0 t=(pi/2)+pi*n 2) 2*sin (t)+1=0 2*sin (t)=-1 sin (t)=-1/2 t=(-1) ^n*arcsin (-1/2)+pi*n t=(7*pi/6)+pi*n г) 2sin (t) -sqrt (2)*(2*cos (t)+1)=0 1) 2*sin (t) -sqrt (2)=0 2*sin (t)=sqrt (2) sin (t)=sqrt (2) /2 t=(pi/4)+pi*n 2) 2*cos (t)+1=0 2*cos (t)=-1 cos (t)=-1/2 t=±arccos (-1/2)+2*pi*n t=± (4*pi/3)+2*pi*n